这里的代码怎么写，蹲一位python大佬

kafei

两个列表
list1 = [1,2,3]
list2 = ['A','B','C']
对应位置的元素相乘
得到一个list3 = ['A','B','B','C','C','C']

求大佬用python实现一下

yjsx86

https://tool.lu/coderunner/embed/bc9.html

teardrops

1. list1 = [1,2,3]
   
2. list2 = ['A','B','C']
   
3. 
   
4. 
   
5. 
   
6. tmp = map(lambda x, y: x*[y], list1, list2)
   
7. list3 = [i for item in tmp for i in item]
   

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汤家凤

1. for i in range(len(list2)):
   
2.       list3+=list2[i]*list1[i]

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His

for i in range(1,len(list2)):
for j in range(1,len(list1)):
  result.append(list2[i])

mubazhe

套两个循环试试

ygvm.com

python大佬都忙着赚钱去了。

exexue

简单 for i in list1 :

pdd_nb

这叫“对应位置元素相乘”?我理解的对应相乘是[1A,2B,3C]...

dunce

His 发表于 2021-6-27 17:12
for i in range(1,len(list2)):
for j in range(1,len(list1)):
  result.append(list2)

1. for i in range(0, len(list2)):
   
2.     for j in range(0, list1[i]):
   
3.         result.append(list2[i])

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